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Therefore
when ABC is a triangle having the angle ABC greater than the angle BCA, the side AC is also greater than the side AB.
Being what it was required to prove.
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T H E E L E M E N T S |
Book I Proposition 19 | |
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It was proved that AC is neither less than nor equal to AB. Therefore when ABC is a triangle having the angle ABC greater than the angle BCA, the side AC is also greater than the side AB. Being what it was required to prove. |
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