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Book I   Proposition 44
Then HLKF is a parallelogram, HK is its diameter, and AG, ME are parallelograms, and LB, BF the so-called complements, about HK; therefore
    LB is equal to BF. [I.43]
But, also,
    the triangle C is equal to BF;
therefore
    LB is also equal to C. [C.N.1]

And, since
    the angle ABM is equal to the angle GBE, [I.15]
while
    the angle D to the angle GEB,
    the angle ABM is also equal to the angle D.
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