T H E E L E M E N T S |
Book I Proposition 24 | |
Again, since DF is equal to DG, the angle DGF is equal to the angle DFG; [I.5] therefore the angle DFG is greater than the angle EGF. Therefore the angle EFG is much greater than the angle EGF. And, since EFG is a triangle having the angle EFG greater than the angle EGF, and the greater angle is subtended by the greater side, [I.19] the side EG is also greater than EF. |
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