T
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E

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Book I   Proposition 24
Again, since DF is equal to DG,
    the angle DGF is equal to the angle DFG; [I.5]
therefore
    the angle DFG is greater than the angle EGF.
Therefore
    the angle EFG is much greater than the angle EGF.

And, since EFG is a triangle having the angle EFG greater than the angle EGF, and the greater angle is subtended by the greater side, [I.19]
    the side EG is also greater than EF.
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