T H E E L E M E N T S |
Book I Proposition 21 | |
Then, since in any triangle two sides are greater than the remaining one, [1.20] therefore, in the triangle ABE, the two sides BA, AE are greater than BE. Let EC be added to each; therefore BA, AC are greater than BE, EC. (continue) Again, since, in the triangle DEC, the two sides DE, EC are greater than DC, let BD be added to each; therefore BE, EC are greater than BD, DC. (continue) Since BA, AC were proved greater than BE, EC and BE, EC are greater than BD, DC; therefore BA, AC are (much) greater than BD, DC. |
||
Previous Page Return to Propositions Next Page |