T H E E L E M E N T S |
Book I Proposition 5 | |
It was shown that
BF is equal to CG and
FC is equal to GB. So, since the two triangles have the two sides BF, FC equal to the two sides CG, GB respectively, and the angle BFC of the one equal to the angle CGB of the other, [then also] the base CB is common with itself and the triangle BFC will be equal to the triangle CGB and the remaining angles will be equal to the remaining angles respectively, those the equal sides subtend. Therefore the angle FBC is equal to the angle GCB and the angle BCF is equal to the angle CBG. |
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