T H E E L E M E N T S |
Book I Proposition 5 | |
Accordingly, since the whole angle ABG was shown to be equal to the whole angle ACF, of which angle CBG is equal to angle BCF, therefore the remaining angle ABC is equal to the remaining angle ACB; and they are at the base of triangle ABC. Of course it was shown that angle FBC is equal to angle GCB; and they are under the base of triangle ABC. |
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